x+3y-[x-y]-[x-(x+y)]=

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Solution for x+3y-[x-y]-[x-(x+y)]= equation:


Simplifying
x + 3y + -1[x + -1y] + -1[x + -1(x + y)] = 0
x + 3y + [x * -1 + -1y * -1] + -1[x + -1(x + y)] = 0
x + 3y + [-1x + 1y] + -1[x + -1(x + y)] = 0
x + 3y + -1x + 1y + -1[x + (x * -1 + y * -1)] = 0
x + 3y + -1x + 1y + -1[x + (-1x + -1y)] = 0

Combine like terms: x + -1x = 0
x + 3y + -1x + 1y + -1[0 + -1y] = 0
x + 3y + -1x + 1y + -1[-1y] = 0

Remove brackets around [-1y]
x + 3y + -1x + 1y + -1 * -1y = 0

Multiply -1 * -1
x + 3y + -1x + 1y + 1y = 0

Reorder the terms:
x + -1x + 3y + 1y + 1y = 0

Combine like terms: x + -1x = 0
0 + 3y + 1y + 1y = 0
3y + 1y + 1y = 0

Combine like terms: 3y + 1y = 4y
4y + 1y = 0

Combine like terms: 4y + 1y = 5y
5y = 0

Solving
5y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '5'.
y = 0

Simplifying
y = 0

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